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7k^2=-24-29k
We move all terms to the left:
7k^2-(-24-29k)=0
We add all the numbers together, and all the variables
7k^2-(-29k-24)=0
We get rid of parentheses
7k^2+29k+24=0
a = 7; b = 29; c = +24;
Δ = b2-4ac
Δ = 292-4·7·24
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-13}{2*7}=\frac{-42}{14} =-3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+13}{2*7}=\frac{-16}{14} =-1+1/7 $
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